Answer
$0.3472$
$0.0694$
$0.0046$
Work Step by Step
Use binomial to simulate the problem, rolling three dice is the same
as roll 1 dice three times. We have $n=3$ and $p=1/6$ is the probability
of getting the number. Thus
To win 1 dollar $P(1)=_3C_1\cdot p^1(1-p)^2=0.3472$
To win 2 dollars $P(2)=_3C_2\cdot p^2(1-p)^1=0.0694$
To win 3 dollars $P(3)=_3C_3\cdot p^3(1-p)^0=0.0046$
