Answer
a. $0.16$
b. $0.42$
c. $0.07$
Work Step by Step
Use the hypergeometric formula or use the procedure below.
Total possible combinations of 4 out of 14 is $_{14}C_4=1001$
a. 3 are girls
Favorable outcomes $_6C_3\times_8C_1=160$
$p=160/1001=0.16$
b. 2 are girls
Favorable outcomes $_6C_2\times_8C_2=420$
$p=420/1001=0.42$
c. 4 are boys
Favorable outcomes $_6C_0\times_8C_4=70$
$p=70/1001=0.07$
