Answer
$\mu=1.5$
$\sigma=0.866$
Work Step by Step
Given $p=2/3$, we have $q=1-p=1/3$.
Using the formula for a geometric distribution, we have
$\mu=1/p=3/2=1.5$
$\sigma=\sqrt {q/p^2}=\sqrt {\frac{1}{3}\times(\frac{3}{2})^2}=0.866$
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