Answer
0.264
Work Step by Step
$p=5/500=0.01, n=100, \mu=np=1$, use Poisson formula
$P(0)=\frac{1^0e^{-1}}{0!}=0.368, P(1)=\frac{1^1e^{-1}}{1!}=0.368$,
$P(X\geq2)=1-P(0)-P(1)=0.264$
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