Answer
a. $0.832$
b. $0.441$
c. $0.336$
Work Step by Step
$p=1/5=0.2, n=8$
a. The probability that at least one began online
$P(X\geq1)=1-P(X=0)=1-0.168=0.832$
b. The probability that two or three began online
$P(X=2)+P(X=3)=0.294+0.147=0.441$
c. What is the probability that exactly one began online?
$P(X=1)=0.336$