Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 5 - Discrete Probability Distributions - 5-2 Mean, Variance, Standard Deviation, and Expectation - Exercises 5-2 - Page 272: 3

Answer

Mean = μ = ∑X * P(X) = (0*0.18)+(1*0.44)+(2*0.27)+(3*0.08)+(4*0.03) = 1.34 Variance = $ σ ^{2}$ = ∑[$X ^{2}$ * P(X)] - $ μ ^{2}$ =[ $0 ^{2}$ *0.18 +$ 1 ^{2}$ * 0.44 + $ 2 ^{2}$ * 0.27 + $ 3 ^{2}$ *0.08 + $ 4 ^{2}$ *0.03 ] -$ 1.34 ^{2}$ =(0+0.44+1.08+0.72+0.48)-1.7956 =2.72-1.7956 =0.9244 Standard Deviation = σ = $ \sqrt σ ^{2}$ = $\sqrt 0.9244$ = 0.9615 The vice president is incorrect since the mean number of credit card own is 1.34 with a deviation of 0.9615. Based on Chebyshev's Theorem, μ + 2σ = 3.263 ~ 4 with a confidence of 75% is owning 4 credit card instead of 3.

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