Answer
No.
Work Step by Step
Rule 1 — each probability must satisfy
$0\leq P(X)\leq 1$
Here $P(12)=-0.8$ is negative, which is impossible for a probability.
Rule 2 — probabilities must sum to 1
Let’s still check the sum:
$0.3+0.5+0.7+(-0.8)=0.7$
That's also not equal to 1.
This is not a valid probability distribution.