#### Answer

$0.727$

#### Work Step by Step

In order to produce berries, the 3 plants must contain
at least one male (4 choices) and one female (8 choices).
When select 3 from 12 plants, these are the favorable outcomes (mmf,mfm,mff, fmm,fmf,ffm).
mmf,mfm,fmm have the probability $p1=3\times\frac{4}{12}\times\frac{3}{11}\times\frac{8}{10}=0.218$
mff,ffm,fmf have the probability $p2=3\times\frac{4}{12}\times\frac{8}{11}\times\frac{7}{10}=0.509$
The total probability is $p1+p2=0.218+0.509=0.727$