# Chapter 4 - Probability and Counting Rules - 4-5 Probability and Counting Rules - Exercises 4-5 - Page 246: 17

$0.727$

#### Work Step by Step

In order to produce berries, the 3 plants must contain at least one male (4 choices) and one female (8 choices). When select 3 from 12 plants, these are the favorable outcomes (mmf,mfm,mff, fmm,fmf,ffm). mmf,mfm,fmm have the probability $p1=3\times\frac{4}{12}\times\frac{3}{11}\times\frac{8}{10}=0.218$ mff,ffm,fmf have the probability $p2=3\times\frac{4}{12}\times\frac{8}{11}\times\frac{7}{10}=0.509$ The total probability is $p1+p2=0.218+0.509=0.727$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.