Answer
a. $p=4/35$
b. $p=1/35$
c. $p=12/35$
d. $p=18/35$
Work Step by Step
The total outcomes are $_7C_3=35$
a. All 3 selected will be women.
Choose 3 women out of 4, $_4C_3=4$, $p=4/35$
b. All 3 selected will be men.
Only on choice, so $p=1/35$
c. 2 men and 1 woman will be selected.
Number of choices $_3C_2$*$_4C_1$=12, $p=12/35$
d. 1 man and 2 women will be selected.
Number of choices $_3C_1$*$_4C_2$=18, $p=18/35$
