#### Answer

0.073

#### Work Step by Step

Here P = 0.52
a. P(All 4 used seat belt) = $(0.52)^{4} = 0.073$

Published by
McGraw-Hill Education

ISBN 10:
0078136334

ISBN 13:
978-0-07813-633-7

0.073

Here P = 0.52
a. P(All 4 used seat belt) = $(0.52)^{4} = 0.073$

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