Answer
$\frac{m+n}{2m+n}$
Work Step by Step
Given P(A)=m/(2m + n), P(B)=n/(2m + n). and P(A and B)=0 (mutually exclusive)
So P(A or B)=P(A)+P(B)=m/(2m + n)+n/(2m + n)=$\frac{m+n}{2m+n}$
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