Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 4 - Probability and Counting Rules - 4-1 Sample Spaces and Probability - Exercises 4-1 - Page 199: 25


a. $\frac{1}{8}$ b. $\frac{1}{4}$ c. $\frac{3}{4}$ d. $\frac{3}{4}$

Work Step by Step

Each child can be a boy or a girl, the total outcome is $N=2\times2\times2=8$ a. All boys There is only 1 favorable outcome, the probability is $p=\frac{1}{8}$ b. All girls or all boys There are 2 favorable outcome, the probability is $p=\frac{2}{8}=\frac{1}{4}$ c. Exactly two boys or two girls There are 6 (bbg,bgb,gbb,ggb,gbg,bgg) favorable outcome, the probability is $p=\frac{6}{8}=\frac{3}{4}$ d. At least one child of each gender This is the same as c. so $p=\frac{3}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.