## Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

a. $\frac{13}{18}$ b. $\frac{1}{6}$ c. $\frac{11}{36}$
a. A sum less than 9 There are 26 (11,12,13,14,15,16,21,22,23,24,25,26,31,32,33,34,35,41,42,43,44,51,52,53,61,62) favorable outcomes. The total out comes are 36 $(6\times6)$. So the probability of getting a sum less than 9 is $p=\frac{26}{36}=\frac{13}{18}$ b. A sum greater than or equal to 10 There are 6 (46,55,56,64,65,66) favorable outcomes. So the probability of getting a sum greater than or equal to 10 is $p=\frac{6}{36}=\frac{1}{6}$ c. A 3 on one die or on both dice. There are 11 (13,23,31,32,33,34,35,36,43,53,63) favorable outcomes. So the probability of getting a 3 on one die or on both dice is $p=\frac{11}{36}$