Answer
Tom, Harry, Dick.
Work Step by Step
Given $\mu=125$ and $\sigma=18$
Tom $x=158$
Harry $z=2.00$, $\frac{x-125}{18}=2$, $x=161$
Dick 98th percentile, empirical rule states that $95\%$ fall within $z=-2, and +2$, so $z=2$ is at 97.5th (95+5/2) percentile. This means that 98th percentile is better than $z=2$ (this can be confirmed by using a z-table)
The ranks are: Tom, Harry, Dick.