## Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education

# Chapter 3 - Data Description - 3-2 Measures of Variation - Exercises 3-2 - Page 146: 42

#### Answer

a. $12.5\%$ b. $2.5\%$

#### Work Step by Step

$\frac{58.6-53}{2.8}=2$ use Chebyshev’s theorem we have $1-1/2^2=0.75$ or $75\%$ of the data within and $25\%$ outside. Assume a symmetric distribution, the percentage of faculty members work more than 58.6 hours a week would be half or $12.5\%$ In this case, we use the empirical rule, there are $95\%$ within and $5\%$ outside. The percentage of faculty members work more than 58.6 hours a week would be $2.5\%$

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