Answer
a. $12.5\%$
b. $2.5\%$
Work Step by Step
$\frac{58.6-53}{2.8}=2$ use Chebyshev’s theorem we have $1-1/2^2=0.75$ or $75\%$ of the data within and
$25\%$ outside. Assume a symmetric distribution,
the percentage of faculty members work more than 58.6 hours a week would be half or $12.5\%$
In this case, we use the empirical rule, there are $95\%$ within and $5\%$ outside.
The percentage of faculty members work more than 58.6 hours a week would be $2.5\%$
