#### Answer

Fail to reject the null hypothesis.

#### Work Step by Step

$H_{0}:\sigma_1=sigma_2,$ $H_{a}:\sigma_1\ne \sigma_2$. :$F=\frac{s_1^2}{s_2^2}=\frac{5.13^2}{5.35^2}=0.9194.$ The critical values by the table with df=min(29,29)=29: $f_{0.025}$ is between 2.0923 and 2.154. If the value of the test statistic is in the rejection region, we reject the null hypothesis. 0.9194 is less than 2.0923, hence we fail to reject the null hypothesis.