#### Answer

Reject the null hypothesis.

#### Work Step by Step

$H_{0}:\mu_d=0,$ $H_{a}:\mu_d\ne0$. The test statistic is:$t=\frac{\overline{d}-\mu_d}{s_d/\sqrt{n}}=\frac{-3657.7083-0}{8490.2467/\sqrt{24}}=-2.111.$ The P is the corresponding probability using the table with df=24-1=23, hence P is between 0.02 and 0.05. If the P-value is less than $\alpha$, which is the significance level, then this means the rejection of the null hypothesis. Hence:P is less than $\alpha=0.05$, hence we reject the null hypothesis. Hence there seems to be difference in the number of words.