#### Answer

3383.

#### Work Step by Step

Using the table: $z_{\alpha/2}=z_{0.05}=1.645.$ Hence the sample size:$n=\frac{z_{\alpha/2}^2}{2E^2}=\frac{1.645^2}{2(0.02)^2}\approx3383.$

Published by
Pearson

ISBN 10:
0321836960

ISBN 13:
978-0-32183-696-0

3383.

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