Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 7 - Estimates and Sample Sizes - Review - Review Exercises - Page 373: 2



Work Step by Step

$\alpha=1-0.99=0.01.$ Using the table: $z_{\alpha/2}=z_{0.005}=2.58.$ Hence the minimum sample size:$\frac{z_{\alpha/2}^2\cdot 0.25}{E^2}=\frac{2.58^2\cdot 0.25}{0.02^2}\approx4160$.
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