Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 7 - Estimates and Sample Sizes - Review - Cumulative Review Exercises - Page 376: 10


a) 0.0001 b)0.9999 c)0.999

Work Step by Step

a) Using the fundamental counting rule the number of outcomes: $10^3=1000.$ $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$, hence $P=\frac{1}{1000}=0.0001.$ b)By using the complement rule and the result from a), P(no success)=1-P(success)=1-0.0001=0.9999. c) Using the multiplication rule and the result from b): $P(no \ success)^{10}=0.9999^{10}=0.999$
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