## Elementary Statistics (12th Edition)

a)$0.667$ b) (4,4); 0 (5,5); 1 (9,9); 1 (4,5); .5 (4,9); .5 (5,4); .5 (5,9); 1 (9,4); .5 (9,5); 1 c) $0.667$ d) Yes
a) We use the equation for probability to find: $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$. $probability=2/3=0.667$ b) The odds of all of the events is the same: $1/9$. Hence we use the same equation as above to find the percentage of odd numbers: (4,4); 0 (5,5); 1 (9,9); 1 (4,5); 0.5 (4,9); 0.5 (5,4); 0.5 (5,9); 1 (9,4); 0.5 (9,5); 1 c) We find the mean: $(4/9)+(0.5)(4/9)=0.667$ d) The sample proportion is unbiased, because the results to part a) and part c) are identical.