Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Basic Skills and Concepts - Page 270: 31


$P_{1}=17.94, P_{2}=30.06$

Work Step by Step

By using the table, the z-score corresponding to 0.01 and 0.99: $z_{1}=-2.33.$ $z_{2}=2.33$ Hence the corresponding values:$mean+z_{1}⋅standard \ deviation=24−2.33⋅2.6=17.94.$ $mean+z_{2}⋅standard \ deviation=24+2.33⋅2.6=30.06.$ These limits can be useful to keep the number of chocolate chips within a certain limit.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.