#### Answer

$P_{1}=17.94,
P_{2}=30.06$

#### Work Step by Step

By using the table, the z-score corresponding to 0.01 and 0.99: $z_{1}=-2.33.$
$z_{2}=2.33$ Hence the corresponding values:$mean+z_{1}⋅standard \ deviation=24−2.33⋅2.6=17.94.$
$mean+z_{2}⋅standard \ deviation=24+2.33⋅2.6=30.06.$ These limits can be useful to keep the number of chocolate chips within a certain limit.