Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Basic Skills and Concepts - Page 268: 22

Answer

a) $46.8$ % b) $98.8$ % c) Between $58.86$ and $74.06$ inches

Work Step by Step

a) We first must find the $z$-scores for each of the ends of the range: $\frac{64−63.8}{2.6}=0.08$ $\frac{77−63.8}{2.6}=5.077$ Using a table of $z$-scores and subtracting the two $z$-scores, we can find that $46.8$ % of women are in this range. b) We use the same process for men: $\frac{64−69.5}{2.4}=−2.29$ $\frac{77−69.5}{2.4}=3.125$ Using a table of $z$-scores and subtracting the two $z$-scores, we can find that $98.8$ % of men are in this range. c) Using a table of $z$-scores, we can find that $z=±1.9$. We now consider the tallest men and the shortest women to get: $max=(1.9)(2.4)+69.5=74.06$ in $min=−(1.9)(2.6)+63.8=58.86$ in
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