#### Answer

120

#### Work Step by Step

By using the table, the z-score belonging to the area 0.9099: z=1.34. $IQ=mean+z\cdot(standard \ deviation)=100+(1.34) \cdot 15=100+20.1=120.1\approx120.$

Published by
Pearson

ISBN 10:
0321836960

ISBN 13:
978-0-32183-696-0

120

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