Answer
Mean:240, standard deviation:12, it is not unusually low or high.
Work Step by Step
Here n=600, p=0.4.
Mean=$n\cdot p=600 \cdot 0.4=240$.
Standard deviation: $\sqrt{n \cdot p \cdot (1-p)}=\sqrt{600 \cdot 0.4 \cdot 0.6}=12.$
If a value is unusual, then it is more than two standard deviations far from the mean. $Minimum \ usual \ value=mean-2\cdot(standard \ deviation)=240-2\cdot12=216$
$Maximum \ usual \ value=mean+2\cdot(standard \ deviation)=240+2\cdot12=264$. Our value is between these two values, therefore it is not unusually low or high.
