Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - Review - Cumulative Review Exercises - Page 238: 3

Answer

a) $0.282$ b) $0.303$ c) $0.242$ d) $0.297$ e) $0.0792$ f) $0.738$ g) $0.703$

Work Step by Step

We know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$. Hence: a) $ P=\frac{121+51}{611}=0.282$ b) $P=\frac{121}{121+279}=0.303$ c) $P=\frac{51}{160+51}=0.242$ d) $P=\frac{51}{121+51}=0.297$ e) We use the result from part a) to find: $P=0.282^2=0.0792$ f) We use the results above to find: $\frac{400}{611}+\frac{51}{611}=0.738$ g) $P=\frac{121}{121+51}=0.703$
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