Answer
We can use the Poisson distribution.
Work Step by Step
The first requirement is satisfied, because n=100, and the requirement is $n\geq100.$ the second requirement is satisfied, because $n\cdot p=100\cdot\frac{1}{1000}=0.1\leq10.$ Both requirements are asatisfied, therefore we can use the Poisson distribution. It is impossible to have 101 wins out of 100 tries.