Elementary Statistics (12th Edition)

Published by Pearson

Chapter 5 - Discrete Probability Distributions - 5-4 Parameters for Binomial Distributions - Beyond the Basics: 21

Answer

Standard deviation=6, p=0.4, n=150.

Work Step by Step

We know that the minimum and maximum usual values are 48 and 72, therefore the mean is 60 and the standard deviation is 6. We also know that standard deviation: 6=$\sqrt{n \cdot p \cdot (1-p)}=\sqrt{mean \cdot (1-p)}=\sqrt{60\cdot (1-p)}$, therefore 1-p=0.6, p=0.4. Mean=$n\cdot p$, therefore n=$\frac{mean}{p}=150$.

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