Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-4 Parameters for Binomial Distributions - Basic Skills and Concepts - Page 227: 15


a) Mean:156. Standard deviation:12.11. b)It is not unusually low or high.

Work Step by Step

Here, n=2600 and p=0.06. a) Mean=$n\cdot p=2600 \cdot 0.06=156$. Standard deviation: $\sqrt{n \cdot p \cdot (1-p)}=\sqrt{2600 \cdot 0.06 \cdot 0.94}=12.11.$ b)If a value is unusual, then it is more than two standard deviations far from the mean. $Minimum \ usual \ value=mean-2\cdot(standard \ deviation)=156-2\cdot12.11=131.78$ $Maximum \ usual \ value=mean+2\cdot(standard \ deviation)=156-2\cdot12.11=180.22$. 178 is between these value, therefore it is not unusually low or high.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.