# Chapter 5 - Discrete Probability Distributions - 5-3 Binomial Probability Distributions - Basic Skills and Concepts - Page 221: 39

a) 0.000854 b) 0.000061 c)0.000915 d)The method seems to be effective.

#### Work Step by Step

a) $P(X=13)={14\choose 13} \cdot (0.5)^{13}\cdot (0.5)^1=0.000854.$ b)$P(X=14)={14\choose 14} \cdot (0.5)^{14}\cdot (0.5)^0=0.000061.$ c)$P(X\geq13)=P(X=13)+P(X=14)={14\choose 13} \cdot (0.5)^{13}\cdot (0.5)^1+{14\choose 14} \cdot (0.5)^{14}\cdot (0.5)^0=0.000854+0.000061=0.000915.$ d)The probability of c) indicates that normally this probability would be very low therefore the method seems to be effective.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.