Elementary Statistics (12th Edition)

a)There are 26 possibilites all with the same probability, hence the expected value is:$\frac{0.1}{26}+\frac{1}{26}+\frac{5}{26}+...+\frac{1,000,000}{26}=131,477.5.$ b)Standard deviation=$\sqrt{\frac{\sum (x-\mu)^2}{n}}=\sqrt{\frac{(0.1-131,477.5)^2+(1-131,477.5)^2+...+(1,000,000-131,477.5)^2}{26}}=253,584.5$ c) $Minimum \ usual \ value=mean-2\cdot(standard \ deviation)=131,477.5-2\cdot253,584.5=-375691.5$ $Maximum \ usual \ value=mean+2\cdot(standard \ deviation)=131,477.5+2\cdot253,584.5=638646.5$. d)Both of the values are more than 638646.5, hence they are both unusually high.