## Elementary Statistics (12th Edition)

a) From the table, the probability of getting exactly 3 failing cars is is: $P(X=3)=0.041.$ b)From the table, the probability of getting at least 3 failing cars is: $P(X≥3)=P(X=3)+P(X=4)+P(X=5)+P(X=6)=0.041+0.005+0+0=0.046.$ c)The result from b) because it gives us the probability for the range of 3 to 6 whilst a) only gives us the probability of 3. d) 3 is an unusually high number of girls, because 0.046<0.05.