# Chapter 5 - Discrete Probability Distributions - 5-2 Probability Distributions - Basic Skills and Concepts: 8

It is a probability distribution, mean:0.4, standard deviation:0.6.

#### Work Step by Step

It is a probability distribution because $\sum P(x)=0.659+0.287+0.05+0.004+0.001+0\approx1$. Mean $0\cdot0.659+1\cdot0.287+2\cdot0.05+3\cdot0.004+4\cdot0.001+5\cdot0=0.4$. Standard deviation: $\sqrt{(0-0.4)^2\cdot0.659+(1-0.4)^2 \cdot0.287+(2-0.4)^2\cdot0.05+(3-0.4)^2\cdot0.004+(4-0.4)^2\cdot0.001+(5-0.4)^2\cdot0}=0.6.$.

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