## Elementary Statistics (12th Edition)

$\frac{1}{12}.$, independent.
Two events are dependent, if the outcome of one effects the outcome of the other. Here the events are independent, because the gender of the child doesn't affect the die, hence here $P(B|A)=P(B)$. $P(A \cap B)=P(A)\cdot P(B|A)$. Hence $P(A \cap B)=\frac{1}{2}\cdot\frac{1}{6}=\frac{1}{12}.$