Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 4 - Probability - 4-3 Addition Rule - Basic Skills and Concepts: 16

Answer

$0.99112$

Work Step by Step

We know that $P(I)+P(\overline{I})=1.$ Therefore tthe probability of randomly screening a driver where the result indicates that he is not intoxicated is: $P(\overline{I})=1-P(D)=1-0.00888=0.99112$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.