## Elementary Statistics (12th Edition)

r (linear correlation coefficient) is given: r=0.091548. Hence the value of the test statistic: $\frac{r}{\sqrt{(1-r^2)/(n-2)}}=\frac{0.091548}{\sqrt{(1-0.091548^2)/(40-2)}}=0.567.$ Using the table, the corresponding P value with df=40-2=38: P is more than 0.2. If the P-value is less than the significance level, then this means the rejection of the null hypothesis. Hence:P is more than 0.05, hence we fail to reject the null hypothesis. Hence we can say that there is not sufficient evidence to support that there is a linear correlation.