#### Answer

The professor awarded A's to about .0668, or 6.68% of the students.

#### Work Step by Step

We use the table of Normal curve areas to find the proportion of the class that was awarded an A. First, go to column A to find the z score of 1.5. Then, use column C to find the proportion of students with a z score of 1.50 or higher (from z). The value from column C is .0668