Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.3 - Polar Form of Complex Numbers; De Moivre's Theorem - 8.3 Exercises - Page 609: 2

Answer

(a) $r=\sqrt {a^2+b^2}$, $tan\theta=\frac{b}{a}$ (b) $z=r(cos\theta+i\cdot sin\theta)$

Work Step by Step

(a) The modulus of z is $r=\sqrt {a^2+b^2}$, and an argument of z is an angle $theta$ satisfying $tan\theta=\frac{b}{a}$ (b) We can express z in polar form as $z=r(cos\theta+i\cdot sin\theta)$ ...
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