Answer
no, infinitely many
Work Step by Step
The basic equation $\sin x=2$ has no solutions, whereas the basic equation $\sin x=0.3$ has infinitely many solutions.
This is because 2 is not in the range of $\sin x$, which can only take on values in $[-1, 1]$, whereas $x=\sin^{-1}0.3+2k\pi$ and $x=(2k+1)\pi-\sin^{-1}0.3$ are solutions of $\sin x=0.3$ for all integers $k$.
