Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.3 - Trigonometric Functions of Angles - 6.3 Exercises - Page 501: 73

Answer

$42.5^\circ$

Work Step by Step

Step 1. Given $\alpha=59.4^\circ, k=1.33$, with $sin\alpha=k\cdot sin\beta$, we have $1.33sin\beta=sin59.4^\circ$ which gives $sin\beta=0.6472$ Step 2. Use the $sin^{-1}$ function on the above result to get $\beta=40.33$ Step 3. $\theta=4\beta-2\alpha=4\times40.33-2\times59.4\approx42.5^\circ$
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