Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Concept Check - Page 527: 12

Answer

$(a)$ $\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$ $(b)$ $a\approx 121.6$ $(c)$ In this kind of case there could be either two, one or no triangle with given sides and angles.

Work Step by Step

$(a)$ According to the Law of Sines, in any triangle ABC we have : $\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$ $(b)$ We can find $a$ using Law of Sines. In this case we have : $\frac{\sin 85°}{a}=\frac{\sin 40°}{b}=\frac{\sin C}{100}$ If we find value of $C$ we can find $a$ too. We know that in any triangle, sum of all angles equals to $180°$, so : $C=180°-(85°+40°)=55°$ $\frac{\sin 85°}{a}=\frac{\sin 55°}{100}$ $a=\frac{100 \sin 85°}{\sin 55°}$ $a\approx 121.6$ $(c)$ In this kind of case there could be either two, one or no triangle with given sides and angles.
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