Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Section 5.5 - Inverse Trigonometric Functions and Their Graphs - 5.5 Exercises - Page 445: 4

Answer

Find the Exact value of each expression. (a). $sin^{-1}(-1)$ = -90 degrees or $-\frac{\pi}{2}$ (b). $sin^{-1}(\frac{\sqrt 2}{2})$ = 45 degrees or $\frac{\pi}{4}$ (c). $sin^{-1}(-2)$ = Not Possible

Work Step by Step

What this problem is saying is that at which angle on the unit circle is sine -1, $\frac{\sqrt 2}{2}$, and -2. Looking at the unit circle find the angle at which the y coordinate is the values you are solving for. The angle at which the y-coordinate is -1 is at -90 or $-\frac{\pi}{2}$. The angle at which the y-coordinate is $\frac{\sqrt 2}{2}$ is 45 degrees or $\frac{\pi}{4}$. As you can see because there is no y coordinate of -2 that means that the angle doesn't exist.
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