Chapter 4 - Section 4.4 - Laws of Logarithms - 4.4 exercises - Page 360: 77

See explanation below

$\log .1 < 2 \log .1$ $ = \log (0.1)^2$ $ = \log (0.01)$ $\log 0.1 < \log 0.01$ $0.1 < 0.01$ This first statement is already incorrect, because $\log .1$ is -1, so $ 2* \log .1 = -2$ And the statement $-1 < -2$ is incorrect, so this is what is at fault for this equation in the "find the error" problem.