Answer
sum;
$\log_5{25}$;
$\log_5{125}$
Work Step by Step
RECALL:
$\log{(a \cdot b)}=\log{a} + \log{b}$
This means that the logarithm of a product of two numbers is equal to the sum of of the logarithms of each number.
Therefore, the missing expressions in the given statement are (in order):
sum;
$\log_5{25}$;
$\log_5{125}$