Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.4 - Laws of Logarithms - 4.4 exercises - Page 358: 1


sum; $\log_5{25}$; $\log_5{125}$

Work Step by Step

RECALL: $\log{(a \cdot b)}=\log{a} + \log{b}$ This means that the logarithm of a product of two numbers is equal to the sum of of the logarithms of each number. Therefore, the missing expressions in the given statement are (in order): sum; $\log_5{25}$; $\log_5{125}$
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