# Chapter 4 - Section 4.4 - Laws of Logarithms - 4.4 exercises - Page 358: 1

sum; $\log_5{25}$; $\log_5{125}$

#### Work Step by Step

RECALL: $\log{(a \cdot b)}=\log{a} + \log{b}$ This means that the logarithm of a product of two numbers is equal to the sum of of the logarithms of each number. Therefore, the missing expressions in the given statement are (in order): sum; $\log_5{25}$; $\log_5{125}$

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