## Precalculus: Mathematics for Calculus, 7th Edition

sum; $\log_5{25}$; $\log_5{125}$
RECALL: $\log{(a \cdot b)}=\log{a} + \log{b}$ This means that the logarithm of a product of two numbers is equal to the sum of of the logarithms of each number. Therefore, the missing expressions in the given statement are (in order): sum; $\log_5{25}$; $\log_5{125}$