Answer
$ID1=5.32$
$ID2=4.32$
Work Step by Step
Given $A=100mm,W1=5mm,W2=10mm$, we have
$ID1=\frac{log(2\times100/5)}{log2}=5.32$
$ID2=\frac{log(2\times100/10)}{log2}=4.32$
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