Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.1 - Exponential Functions - 4.1 Exercises - Page 338: 62

Answer

$\$ 67, 121.04$

Work Step by Step

Need to use formula: $A(t)=P(1+\dfrac{r}{n})^{nt}$ Here, we have $A(5)=10000=P(1+\dfrac{0.08}{12})^{(12)(5)}$ or, $10000=P(1+\dfrac{0.08}{12})^{60}$ or, $P=\dfrac{10000}{(12.08/12)^{60}}=\$ 67, 121.04$
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