Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.1 - Exponential Functions - 4.1 Exercises - Page 337: 51

Answer

See step by step proof below.

Work Step by Step

We prove the equation by substituting the function $f(x)=10^x$ to the left side of the expression: $\frac{f(x+h)-f(x)}{h}=\frac{10^{x+h}-10^x}{h}=\frac{10^x10^h-10^x}{h}=\frac{10^x(10^h-1)}{h}$ Thus we proved that $\frac{f(x+h)-f(x)}{h}=10^x(\frac{10^h-1}{h})$
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