Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.1 - Exponential Functions - 4.1 Exercises - Page 336: 24

Answer

$f(x)=\left(\dfrac{1}{2}\right)^x$

Work Step by Step

Substituting $x= -3 $ and $f(x)= 8 $ in the given function, $f(x)=a^x$, then the value of $a$ is \begin{array}{l}\require{cancel} 8=a^{-3} \\\\ 8=\dfrac{1}{a^3} \\\\ a^3=\dfrac{1}{8} \\\\ a=\sqrt[3]{\dfrac{1}{8}} \\\\ a=\dfrac{1}{2} .\end{array} Hence, the equation of the given graph is $ f(x)=\left(\dfrac{1}{2}\right)^x .$
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