## Precalculus: Mathematics for Calculus, 7th Edition

$-1, 1, -2, 2, -4, 4, -8, \text{ and } 8$
Note that: $-8 = 4(-2) \\-8 =-4(2) \\-8=8(-1) \\-8=-8(1)$ So the factors of $-8$ are $\pm1, \pm2, \pm4, \pm8$. while $\\2=2(1) \\2=(-2)(-1)$ So the factors of $2$ are $\pm1, \pm2$ Thus, The possible values of $p$ are $\pm1, \pm2, \pm4, \pm8$. The possible values of $q$ are $\pm1, \pm2$ Therefore the possible rational zeros $\frac{p}{q}$ of $R(x)$ are: $\\-1, 1, -2, 2, -4, 4, -8, \text{ and } 8$