#### Answer

$\dfrac{2x^5+x^3-2x^2_3x-5}{x^2-3x+1} = 2x^3+6x^2+17x+43+\frac{115x-48}{x^2-3x+1}$

#### Work Step by Step

Use long division to have:

Published by
Brooks Cole

ISBN 10:
1305071751

ISBN 13:
978-1-30507-175-9

$\dfrac{2x^5+x^3-2x^2_3x-5}{x^2-3x+1} = 2x^3+6x^2+17x+43+\frac{115x-48}{x^2-3x+1}$

Use long division to have:

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